3consecutive integers are such that the when the smallest is multiplied by 3 is 18 more than the largest

10 , 11 , 12

Step-by-step explanation:

Let the integers be : x , x + 1 and x + 2

the smallest multiplied by 3 implies 3x

From the first statement

3x = 18 + (x+2)

3x = 18 + x + 2

3x - x = 18 + 2

2x = 20

x = 10

Therefore : the numbers are : 10 , 10 + 1 and  10 + 2

the numbers are : 10 , 11 , 12

10,11,12

Step-by-step explanation:

3 consecutive integers...x and x + 1 and x + 2

3x = x + 2 + 18

3x = x + 20

3x - x = 20

2x = 20

x = 20/2

x = 10

x + 1 = 10 + 1 = 11

x + 2 = 10 + 2 = 12

ur numbers are 10, 11, and 12

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

i pretty sure it is