Astore is having a sale on jelly beans and almonds. for 6 pounds of jelly beans and 2
pounds of almonds, the total cost is $16 . for 3 pounds of jelly beans and 5 pounds of almonds, the total cost is $13. find the cost for each pound of jelly beans and each pound of almonds.

The cost of each pound of jelly beans is $ 2.25 and cost of each pound of almond is $ 1.25

Solution:

Let the cost of each pound of jelly beans is "a"

Let the cost of each pound of almond is "b"

For 6 pounds of jelly beans and 2  pounds of almonds, the total cost is $16

Therefore, we frame a equation as:

6 pounds of jelly beans x cost of each pound of jelly beans + 2  pounds of almonds x cost of each pound of almond = 16

6a + 2b = 16 --------- eqn 1

For 3 pounds of jelly beans and 5 pounds of almonds, the total cost is $13

Therefore, we frame a equation as:

3 pounds of jelly beans x cost of each pound of jelly beans + 5 pounds of almonds x cost of each pound of almond = 13

3a + 5b = 13 ----------- eqn 2

Let us solve eqn 1 and eqn 2

Multiply eqn 2 with 2

6a + 10b = 26 --------- eqn 3

Subtract eqn 1 from eqn 3

6a + 10b = 26

6a + 2b = 16

( - ) -------------------------

8b = 10

Substitute b = 1.25 in eqn 1

6a + 2(1.25) = 16

6a + 2.5 = 16

6a = 13.5

Thus cost of each pound of jelly beans is $ 2.25 and cost of each pound of almond is $ 1.25

points are handed out whenever you post answers.

brainliest answers are handed out by the person asking the question, so whether your answer is picked depends entirely on whether the asker bothers to pick

if you're asking about your rank, it depends on having a certain number of points and a certain number of brainliest answers. for example, at the time of this writing, i have 44338 points out of 15000 needed for the next (nearly triple the requirement! ) but i only have 24 out of 50 required brainliest answers. this number decays, meaning after a certain amount of time (i think about a month), the total number of brainliest answers you've earned doesn't count toward this total. (i've been stuck at the same rank for a long

the lesson to learn here is that you shouldn't worry about points or rank. chances are, no matter how good an answer you may provide, your efforts will go mostly unnoticed unless you focus on the newest/most active questions that get posted.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2