Which of the statements is true for the two equations below?
equation a: 6+3x=3x-3
equation b: 2(4x-1)=8x-2
a. equation a has no solution and equation b has an infinite number of solutions.
b. equation a has an infinite number of solutions and equation b has no solution.
c. equation a and equation b have an infinite number of solutions.
d. equation a and equation b have no solution.

Equation A:

6 + 3x = 3x - 3    

This equation has no solution, no matter what number you plug into the equation, it will never = each other

[if you tried simplifying more]

9 + 3x = 3x         (added 3 on both sides, then subtracted 3x on both sides)

9 = 0

Equation B:

2(4x - 1) = 8x - 2      Distribute/multiply 2 into (4x - 1)

(2)4x - (2)1 = 8x - 2

8x - 2 = 8x - 2      

This will have an infinite number of solutions because whatever number you plugged in, they would always = each other since they are the same on both sides of the equation

[simplified]

8x = 8x       (add 2 on both sides, then divide 8 on both sides)

x = x

Your answer is A

walter needs to make at least 5 more cookies but no more than 40. 5 ≤ x ≤ 40

step-by-step explanation:

20 ≤ x + 15 ≤ 55

subtract 15 from all parts

20-15 ≤ x + 15-15 ≤ 55-15

5 ≤ x ≤ 40

this means how many more cookies he has to make

walter needs to make at least 5 more cookies, but no more than 40 cookies; 5 ≤ x ≤ 40

actually your concept is wrong

step-by-step explanation:

150% of x =300

150x=300×100

x=(300×100)÷150

x=200