which of the graphs below correctly solves for x in the equation −x2 − 3x − 1 = −x − 4?

graph of quadratic opening downward and linear sloping up to the right. they intersect at point negative 4, negative 2 and point 0, 2.
graph of quadratic opening upward and linear sloping up to the right. they intersect at point 0, 2 and point 4, 6.
graph of quadratic opening downward and linear sloping up to the left. they intersect at point negative 3, negative 1 and point 1, negative 5.
graph of quadratic opening upward and linear sloping up to the right. they intersect at point 2, 0.

Graph of quadratic opening downward and linear sloping up to the left. They intersect at point negative 3, negative 1 and point 1, negative 5

Step-by-step explanation:

we have

we can separate the expression above into two equations

----> equation A

This is a quadratic equation ( vertical parabola) open downward (the leading coefficient is negative)

----> equation B  

This is a linear equation with negative slope (decreasing function).so linear sloping up to the left

The solution of the original expression are the x-coordinates of the intersection point both graphs

using a graphing tool

The intersection points are (-3,-1) and (1,-5)

see the attached figure

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.

i dont get the question

step-by-step explanation: