at a football game, a vender sold a combined total of 213 sodas and hot dogs. the number of sodas sold was two times the number of hot dogs sold. find the
number of sodas and the number of hot dogs sold.

142 sodas and 71 hot dogs are sold

Solution:

Let "a" be the number of sodas sold

Let "b" be the number of hot dogs sold

At a football game, a vender sold a combined total of 213 sodas and hot dogs

Therefore,

number of sodas sold + number of hot dogs sold = 213

a + b = 213 eqn 1

The number of sodas sold was two times the number of hot dogs sold

Number of sodas sold = two times the number of hot dogs sold

a = 2b eqn 2

Let us solve eqn 1 and eqn 2

Substitute eqn 2 in eqn 1

2b + b = 213

3b = 213

b = 71

Substitute b = 71 in eqn 2

a = 2(71)

a = 142

Thus 142 sodas and 71 hot dogs are sold

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

7.25

step-by-step explanation:

we know that 7 equals to 7.0. we also know that 1/4=0.25. so we can add the two together and we get 7.25