Jk−0.2k\dfrac jk -0.2k k j −0.2k start fraction, j, divided by, k, end fraction, minus, 0, point, 2, k when j=25j=25 j=25 j, equals, 25 and k=5k=5 k=5 k, equals, 5 .

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

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answer: it's a

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

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step-by-step explanation: