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yachts a and b depart from the same point. yacht a sails 11 km on the bearing 034°. yacht b
sails 14 km on the bearing 124°. find the distance and bearing of yacht b from yacht a.

yor answer is 7/6 times 5

step-by-step explanation:

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐