Aplane flew between two cities at 330 mph, a car went the same distance at 55 mph . if the car took 7.5 hours longer how far apart were the two cities

The cities are 495 miles apart.

Step-by-step explanation:

Let x represent the distance between the two cities.

Let t represent the time taken by the plane to fly between the two cities.

The plane flew between two cities at 330 mph.

Distance = speed × time

Distance covered by the plane would be

330 × t = 330t

A car went the same distance at 55 mph. If the car took 7.5 hours longer, means that the time spent by the car would be (t + 7.5) hours and distance travelled would be

55(t + 7.5) = 55t + 412.5

Since the distance is the same, then

330t = 55t + 412.5

330t - 55t = 412.5

275t = 412.5

t = 412.5/275

t = 1.5

the distance between the two cities would be

1.5 × 330 = 495 miles

3 1/3 x 2 3/5 = 8 2/3

step-by-step explanation:

just multiply the first number by the second number to get your answer.

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation: