Solve this system of equations algebraically:

y – 10 = 11x + x2

y – 12x = 30

the first solution is (–4, –18).

the second solution is (, ).

Y - 10 = 11 x + x²
y - 12x = 30

y = 12 x + 30
12 x + 30 - 10 = 11 x + x²
x² - x - 20 = 0
x (12) = 1+/- √ (1 + 80 ) /2
x 1 = (1 - 9) / 2 = -4
x 2 = ( 1 + 9 ) /2
x 2 = 5
y 2 = 30 + 12 · 2 = 30 + 60 = 90
The second solution is:
( 5, 90 ).  

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