John is 3 years older than jim. jim is 4 years less than twice david’s age. how old are the three boys if their ages add up to 35?

15  years , 12  years , 8 years.

Step-by-step explanation:

Given:

John is 3 years older than Jim.

Jim is 4 years less than twice David’s age.

Ages of three boys add up to 35.

Question asked:

How old are the three boys?

Solution:

Let age of David =

Let age of Jim =

Then age of John will be =

As Jim is 4 years less than twice David’s age

Equation will be  ,

Multiplying both side  by 2

                       =  (let equation 1 )

As ages of three boys add up to 35.

Equation will be,

                           =

Subtracting both side by 3

                           =  

                          =  (let equation 2 )

subtracting equation 1 and 2,we get

                           =  

                          =  

                          =  

                          =

dividing both side by 5

                              (David ages)

Then  ( age of Jim)  

                                    =

                                    =

Then age of John will be,

                                            =

Thus, age of John = 15 years

Age of Jim = 12 years

Age of David = 8 years

don't report but were is the digram

step-by-step explanation:

step-by-step explanation:

*calories burned = (weight)(calorie factor)*

calories burned = 180 (0.65)

calories burned = 117

the calories he used up is 117, which is 65% of his weight.