Locate the relative extremum and point of inflection. use a graphing utility to confirm your results. y = 3x^2 ln x/2 relative extremum (x, y) = point of inflection (x, y) =

Relative Extrema: \left(\frac{2}{\sqrt{e}},-\frac{6}{e}\right)

Step-by-step explanation:

There is only one extreme minimum point that is \left(\frac{2}{\sqrt{e}},-\frac{6}{e}\right) and there is no any point of reflection for this function.

You can find it in attached pictures of graphs.

step-by-step explanation:

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form