Did i do this right?
find the equation of the axis of symmetry for the parabola
y=x^2-8x+5

used y=ax^2+bx+c and got a=1 b=-8 and c=5

then used the formula x=-b/2a and plugged that in and got x=- -8/2(1) and simplified to get x=4 as the axis of symmetry.

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

it shoild be o

step-by-step explanation:

3,6 and 7.

step-by-step explanation:

a) unit place of 37 is 7

so the unit place of cube of 37 will be

7³= 343=3

the answer is 3.

b) unit place of 56 is 6, so the unit place of cube of 56 will be

6³= 216=6

the answer is 6.

c) unit place of 133 is 3, so the unit place of cube of 133 will be

3³= 27= 7.

the answer is 7.