Which equation is y = 6x2 + 12x – 10 rewritten in vertex form?

The equation y = 6x2 + 12x – 10 can be written in vertex form as; y = 6(x + 1)² - 16.

To re-write the equation y = 6x² + 12x – 10 in vertex form, the completing the square method is used as follows;

First, we isolate x- terms and factorise;

By rewriting as perfect squares: we have

Consequently, the equation in vertex form is;

The vertex is therefore given by coordinates; (-1,-16).

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Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

where

(h,k) is the vertex of the parabola

In this problem we have

Convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

Factor the leading coefficient

Complete the square. Remember to balance the equation by adding the same constants to each side

Rewrite as perfect squares

-------> equation in vertex form

The vertex is the point

2 is the final ! : )

answer

the correct answer is

explanation

the given function is

the excluded values are obtained by solving:

we factor to obtain:

the excluded values are