Which equation is y = 6x2 + 12x – 10 rewritten in vertex form?

The equation y = 6x2 + 12x – 10 can be written in vertex form as; y = 6(x + 1)² - 16.

To re-write the equation y = 6x² + 12x – 10 in vertex form, the completing the square method is used as follows;

First, we isolate x- terms and factorise;

By rewriting as perfect squares: we have

Consequently, the equation in vertex form is;

The vertex is therefore given by coordinates; (-1,-16).

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Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

where

(h,k) is the vertex of the parabola

In this problem we have

Convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

Factor the leading coefficient

Complete the square. Remember to balance the equation by adding the same constants to each side

Rewrite as perfect squares

-------> equation in vertex form

The vertex is the point

the answer is $42.96

step-by-step explanation:

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: