On an indoor circular track of circumference 50 feet, joneal starts at point $s$, runs in a counterclockwise direction, and then stops when he has run exactly one mile (5280 feet). on which quarter of the circle, $a$, $b$, $c$ or $d$, did joneal stop

He stoped on 3th quarter,i.e, $C$.

Step-by-step explanation:

He ran 105 full circles ( 5280/50=105 ( rst= 30ft) ). So in the last circles he started from point S to run 30ft more.

The quarter of the circle is long 50ft/4= 12,5ft. So for 30 feets he must run 2 quarters, its 25ft. The last 5ft he ran on the 3th quarter, so he stoped on C.

This answer $C$, if $C$ is the 3th quadrant, i don't see the picture of the track.

step-by-step explanation:

1. practice, practice & more practice

2. review errors

3. master the key concepts

do not try to memorise the processes.

4. understand your doubts.

5. create a distraction free study environment

6. create a mathematical dictionary

7. apply maths to real world problems.

the terms of a geometric sequence can be found by beginning with the first term and multiplying by the common ratio repeatedly. a recursive formula for a geometric sequence with common ratio r is given by an=ran−1 a n = r a n − 1 for n≥2 n ≥ 2 .

step-by-step explanation: