Derive a relationship between depth and temperature, then substitute that into the density/temperature relationship and use the equation from the text to solve the integral and pressure difference. what is the gage pressure at the bottom of the lake? what is the absolute pressure at the bottom of the lake?

And the absolute pressure at the bottom would be:

Step-by-step explanation:

From the figure attached we know the following two conditions:

And we want a linear model like this one:

Where m abd b represent the slope and intercept.

We can find the slope with the following expression:

And then we can find the intercept using the first point:

So then the linear model is:

Assuming the following formula for the density:

If we replace the expression for T into the density we got:

Since the units for are g/ml we can convert this into kg/m^3 multiplying by 1000 and we got:

Then we have the following differential equation:

If we replace the expression for the density in terms of z we got:

And we can separate like this:

Now w can integrate both sides and we got:

And that would be the expression for the change of pressure:

For our case we have 20m of difference between the surface and the bottom so then the change of pressure between these two levels is:

We know that the pressure increase with the depth. So then the gage pressure at the bottom would be:

And the absolute pressure at the bottom would be:

2.56 is the width of the garden

step-by-step explanation:

option a is correct.

step-by-step explanation:

scale factor: it is used to find proportional measurements.

proportions means having the same ratio.

scale factor is the ratio of the model measurement to the actual measurement in a simplest form.

or we can say that the ratio of any two corresponding lengths in two similar geometric figures

if the scale factor is more than 1, then it is an enlargement,

if the scale factor less than 1, then it is a reduction.

given the two geometric figure:

by definition of proportions, we have