Agardener uses a wheelbarrow to move soil from a truck to his garden. on the first trip from the truck to the garden, the wheelbarrow
is half-full of soil and the gardener applies a certain force to cause it to accelerate. on the second trip, the wheelbarrow is full of soil.
although the gardener applies the same amount of force to the wheelbarrow, he cannot move it with the same rate of acceleration.
what should the gardener do to move the wheelbarrow at the same rate of acceleration for the second trip?
a. reduce the amount of soil by one-half and apply the same amount of force
b. keep the amount of soil the same and apply less force
c. reduce the amount of soil by one-quarter and apply the same amount of force
d. double the amount of soil, and apply less force
reset
reset
submit
1 of 10 answered
session timer: 4: 08
session score: 0% (0/1)

Step-by-step explanation:

it seems to me that if he wants the same rate of acceleration as the first trip, then he would need the same amount of soil as the first trip.

Therefore, he should reduce the amount of soil by one half and apply the same force. <

Because the first time it was half fulland since the second trip was all the way full, if he reduced it by one half, it would contain the same amount as the first tripso he can then get the same rate of acceleration.

3.4 pizzas

step-by-step explanation:

given is a scatter plot showing number of pizzas sold during weeks for different issues of coupon

y represents number of pizzas sold and x number of coupons issued

y is marked verticaly and x horizontally

the trend line is given as

y =3.4x+43

this says that even when no coupon is issued pizzas sold will be 43

and rate of change of pizza sold for 1 unit of coupon = slope = 3.4

i.e. when x increases by 1 unit y increases by 3.4 units

hence for each additional coupon issued 3.4 pizzas more will be sold