What is the y-value in the solution to this system of linear equations?
4x + 5y = -12
-2x + 3y = -1

x = -31/22, y= -14/11

Step-by-step explanation:

4x + 5y = -12….(1)

-2x + 3y = -1.……..(2)

multiply equation (2) by 2

-4x + 6y = -2..….(3)

solving equation (1) and (3) by elimination method, we add equations (1) and (3)

11y = -14

y= -14/11

substitute y= -14/11 for the value of x in equation (2)

-2x + 3(-14/11) = -1

-2x = 42/11 - 1= 31/11

x = -31/22

x = -31/22, y= -14/11

Step-by-step explanation:

4x + 5y = -12….(1)

-2x + 3y = -1.……..(2)

multiply equation (2) by 2

-4x + 6y = -2..….(3)

solving equation (1) and (3) by elimination method, we add equations (1) and (3)

11y = -14

y= -14/11

substitute y= -14/11 for the value of x in equation (2)

-2x + 3(-14/11) = -1

-2x = 42/11 - 1= 31/11

x = -31/22

more detail

step-by-step explanation:

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb