How many liters of a 20% solution of acid should be added to 10 liters of a 30% solution of acid to obtain a 25% solution?

liters

10 urgent points

plz

10 liters

Step-by-step explanation:

Let

x ----> liters of a 20% solution of acid

we know that

The number of liters of a 20% solution of acid, multiplied by 0.20 (20% in decimal form) plus 10 liters of a 30% solution of acid multiplied by 0.30 (30% in decimal form) must be equal to the amount of (x+10) liters multiplied by 0.25 (25% in decimal form)

so

The linear equation that represent this problem is equal to

solve for x