Compute the radius of the largest circle that is internally tangent to the ellipse at $(3,0),$ and intersects the ellipse only at $(3,0).$

radius of the largest circle is Zero.

Step-by-step explanation: A circle can't fit into an ellipse with such coordinate (3,0). What that coordinate means is that the ellipse lies along the x axis 3unit from the origin along the x axis and 0 unit from the origin along the y axis. At which no circle can fit in.

Moreso, the the coordinates at which the circle intercepts the ellipse as to be uniform not (3,0).

A circle as a constant radii coordinate on both axis.

I believe you can now see why my answer is Zero.

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

853.3

step-by-step explanation: