If p(x) = x2 - 1 and (x) = 5(x-1), which expression is equivalent to (p – 9)(x)?
5(x - 1) – x2 - 1
(5x - 1) – (x2 - 1)
(x2 - 1) – 5(x - 1)
(x2 - 1) – 5x - 1

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

answer: 88

step-by-step explanation:

so what is the problem what are they asking you to solve

step-by-step explanation:

so what is the problem what are they asking you to solve

1 and 0

step-by-step explanation: