How to solve thus using system of equations: 3x+4y=7 2x-y=-6

you can solve by using elimination method

the value of x is 2 and y is -3

2x-y=7 equation i

3x+4y=6 equation ii

multiplying equation i by 4 and solving equation i and ii

or, 4(2x-y=7)

3x+4y=-6

or, 8x-4y=28

3x+4y=-6

or, 11x=22

: . x=2

putting the value of x in equation i

or, 2x-y=7

or, 2×2-y=7

or, 4-y=7

or, 4-7=y

: . y=-3

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

30

step-by-step explanation:

times by times