Acircle has the equation x2+y2−14x−18y+105=0.
what is the equation of the circle in standard form, the location of its center, and the length of its radius?

the equation of the circle is (x+7)2+(y+9)2=25; the center is at (−7,−9), and the radius is 5 units.
the equation of the circle is (x+7)2+(y+9)2=89; the center is at (−7,−9), and the radius is 89−−√ units.
the equation of the circle is (x−7)2+(y−9)2=415; the center is at (7,9), and the radius is 415−−−√ units.
the equation of the circle is (x−7)2+(y−9)2=25; the center is at (7,9), and the radius is 5 units.

The answer to your question is the last option

Equation in standard form =   (x - 7)² + (y - 9)² = 5²  

Center = (7, 9)

Radius = 5

Step-by-step explanation:

Equation

                         x² + y² - 14x - 18y + 105 = 0

- Grouping property

                       (x² - 14x      )  + (y² - 18y       )   = -105

- Complete perfect square trinomials

                       (x² - 14x + 7²) + ( y² - 18y + 9²) = -105 + 49 + 81

- Factor

                       (x - 7)² + (y - 9)² = 25

or                     (x - 7)² + (y - 9)² = 5²  

Center = (7, 9)

Radius = 5

c

step-by-step explanation: