Aboat took 5 h to travel 60 km up a river, against the current. the return trip took 3 h. find the speed of the boat in still water and the speed of the current.

Correct V₁ boat = 16 km/h and V₂ current = 4 km/h

Step-by-step explanation:

If we take speed (velocity) of the boat as V₁ and speed of the current V₂

Let us form equations:

Traveling down the current  V₁ + V₂ = 60/3 = 20 km/h

Traveling against the current  V₁ - V₂ = 60/5 = 12 km/h

V₁ - V₂ = 12

V₁ + V₂ = 20

If we add up the left and right sides of the equations we get:

2 V₁ = 32  =>    V₁ = 32/2 = 16 km/h

from the second equation we get:

V₂ = 20 - V₁ = 20 - 16 = 4 km/h

V₂ = 4 km/h

God is with you!!!

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

it’s the first one your welcome