Aquality measurement for cabinet manufacturers is whether a drawer slides open and shut easily. historically, 2% of drawers fail the easy slide test. a manufacturer samples 10 drawers from a batch. assuming the chance of failure is independent between drawers, what type of distribution could be used to model the number of failed drawers from the sample of 10?

Binomial distribution could be used to model the number of failed drawers from the sample of 10.

Step-by-step explanation:

We are given the following information:

We treat drawers fail the easy slide test as a success.

P(drawers fail the easy slide test) = 2% = 0.02

The chance of failure is independent between drawers.

A manufacturer samples 10 drawers from a batch.

Since,

Then the number of drawers that fail the easy slide test follows a binomial distribution, where

where n is the total number of trails, x is the number of success, p is the probability of success.

Here, the parameters of binomial distribution are

n = 10, x = number of failed drawers(discrete values, x = 0, 1,...,10), p = 0.02

start with a line segment pq that we will copy. mark a point r that will be one endpoint of the new line segment. set the compasses' point on the point p of the line segment to be copied. adjust the compasses' width to the point q. the compasses' width is now equal to the length of the line segment pq.

step-by-step explanation:

the volume is the product of the area of the base, 3x(3x+4), and the height, 3x-1

step-by-step explanation: