Kathy and her brother clay recently ran in a local marathon. the distribution of finishing time for women was approximately normal with mean 259 minutes and standard deviation 32 minutes. the distribution of finishing time for men was approximately normal with mean 242 minutes and standard deviation 29 minutes. what is the probability of the menand women running a marathon time of less than 2 hours?

P (X<120)=0

Step-by-step explanation:

We can compute the probability for women:

μ=259  and  σ=32

P ( X<120 )=P ( X−μ<120-259 )=P ((X−μ)/σ<(120−259)/32)

Since (x−μ)/σ =Z

and  

we have:

Use the standard normal table to find this area.

Now we can find  P ( Z<4.34 )  by using the standard normal table which is 1:

Therefore: P (X<120)=0

For men

μ=242  and  σ=29

P ( X<120 )=P ( X−μ<120-242 )=P ((X-μ)/σ <(120-242)/29  )

Since (x-μ)/σ=Z

and  

we have:

Use the standard normal table to find this area.

Now we can find  P ( Z<4.21 )  by using the standard normal table which is 1:

Therefore: P (X<120)=0

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3