Five cards are dealt from a standard 52-card deck. what is the probability that we draw (a) 3 aces and 2 kings? (b) a "full house" (3 cards of one kind, 2 cards of another kind)?

 a) 9.23×10⁻⁶ and b) 0.00144

Step-by-step explanation:

Since we have given that

Number of cards = 52

a) Probability that we draw 3 aces and 2 kings.

As we know that

Number of aces = 4

Number of kings = 4

Number of cards drawn = 5

So, the probability becomes,

(b) a "full house" (3 cards of one kind, 2 cards of another kind)

Since there are 13 sets of each type  and we have to select and 2 kinds of it, so, it becomes

So, it becomes,

Hence, a) 9.23×10⁻⁶ and b) 0.00144

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23

25.3

step-by-step explanation:

1st step

add 3+6

=9

multipy 9*3

=37