"fruit juice may be fueling pudgy preschoolers, study says" is the title of an article that appeared in the san luis obispo tribune. this article describes a study that found that for 3- and 4-year-olds, drinking something sweet once or twice a day doubled the risk of being seriously overweight one year later. the authors of the study state total energy may be a confounder if consumption of sweet drinks is a marker for other dietary factors associated with overweight (pediatrics, no vem ber 2005). give an example of a dietary factor that might be one of the potentially confounding variables the study authors are worried about.

Step-by-step explanation:

Hello!

A confounding variable is any variable that may affect the response variable other than the explanatory variable defined by de investigator.

For this example, the objective is to test if drinking something sweet once or twice a day doubles the risk of being seriously overweight one year later.

The explanatory variable is X: Number of sweet drinks a 3- 4- year old kid has a day (one or two)

The response variable Y: Risk of having overweight of a 3- 4- year old kid

Any other variable that modifies the risk of having overweight.

For example:

X: Weekly amount of exercise.

X: Diet of the kid (Fast Food, Sweets, balanced diet)

X: History of obesity in the family of the child.

X: Health status of the child.

I hope it helps!

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!