The net weight in pounds of a packaged chemical herbicide is uniform for 49.62 < x < 50.04 pounds.
(a) determine the mean of x. (round your answer to 2 decimal places.) pounds
(b) determine the variance of x. (round your answer to 4 decimal places.) pounds2
(c) what is p(x < 50.1)

a)

b)

c)

But we see that the distribution is defined ust between 49.62 and 50.04

And in order to find this we can use the CDF (Cumulative distribution function) given by:

And if we replace we got:

And makes sense since all the values are between 49.62 and 50.04

Step-by-step explanation:

For this case we define the random variable X ="net weigth in pounds of a packaged chemical herbicide" and the distribution for X is given by:

Part a

For the uniform distribution the expected value is given by where X is the random variable, and a,b represent the limits for the distribution. If we apply this for our case we got:

Part b

The variance for an uniform distribution is given by:

And if we replace we got:

Part c

For this case we want to find this probability:

But we see that the distribution is defined ust between 49.62 and 50.04

And in order to find this we can use the CDF (Cumulative distribution function) given by:

And if we replace we got:

And makes sense since all the values are between 49.62 and 50.04

18

step-by-step explanation:

ik this stuph and i am smart donkey

assuming you mean addition: addition and subtraction are reverse operations.

step-by-step explanation: