Consider a triangle formed by connecting the three points: (0 0 0), (1 0 0), (1 1 1). a. find the vector which is perpendicular to the surface of this triangle, and has a positive z-direction?

=k−j   or (0 -1 1)

Step-by-step explanation:

The Vector or Outer Product two vectors, say →x&→y, is  

denoted by →x×→y, is a perpendicular vector to the plane containing them.

The given pts. A (0 0 0), B (1 0 0), C (1 1 1) lie in a

plane ABC.

As suchType equation here., the vectors (→(AB ) )and (→AC ) are members, ∈ of the plane ABC

That is □(→(AB )×(→AC))  to the plane ABC

(→(AB ) )=(1-0,0-0,0-0)=(1,0,0)

(→(AC ) )=(1-0,1-0,1-0)=(1,1,1)

(→(AB )×(→AC=  (0i -j  k)

=k−j  

Which is in the positive Z direction

step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it