You spend $27 on 7 bags of candy to throw while you participate in a parade. the bags cost either $5 or $3. how many bags of each amount did you purchase?

Step-by-step explanation:

x = $ 5 bags and y = $ 3 bags

x + y = 7this one is dealing with the number of bags

5x + 3y = 27this one is dealing with the cost

x + y = 7x = 7 - y

now we sub 7 - y in for x, back into the other equation

5(7 - y) + 3y = 27

35 - 5y + 3y = 27

-5y + 3y = 27 - 35

-2y = - 8

y = -8 / -2

y = 4 <=== there are 4 three dollar bags

x + y = 7

x + 4 = 7

x = 7 - 4

x = 3 < there are 3 five dollar bags

it will cost dollar $540

the living room is 3 which means if we divide 325/3 then we get $108

therefore if 1part of the living room cost $108 and 3 costed $325

then total 5part of the room will cost 5*108 which gives $540

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1