Find a polynomial f(x) of degree 4 with real coefficients and the following zeros.

−2 (multiplicity 2) , i

f(x)=

  f(x) = x^4 +4x^3 +5x^2 +4x +4

Step-by-step explanation:

If "a" is a zero, then (x-a) is a factor. The conjugate of a complex zero is also a zero if the polynomial has real coefficients. Then the factorization is ...

  f(x) = (x -(-2))(x -(-2))(x -i)(x -(-i)) = (x^2 +4x +4)(x^2 +1)

  f(x) = x^4 +4x^3 +5x^2 +4x +4

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.