How do the solutions of a system of linear equations appear on a graph

Both the straight-line graph of the two linear equations will pass through the solution point.  

Step-by-step explanation:

Let there is a system of linear equations :

ax + by + c = 0 (1) and

px + qy + r = 0 (2)

If we solve those two equations algebraically, then we will get a solution for the system. Let the solution be (h,k).

So, this point (h,k) will satisfy both equation (1) and equation (2).

Graphically, if we plot the linear equation on the coordinate plane then we will get two different straight lines one for equation (1) and another for equation (2).

Now, (h,k) point on the coordinate plane through which both the straight line will pass.

If the two straight lines are parallel then there will be no solution i.e. there will be no point through the two straight lines will pass.

this is a very good question

step-by-step explanation:

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-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3