Afamily has two cars. the first car has a fuel efficiency of 40 miles per gallon of gas and the second has a fuel efficiency of 25 miles per gallon of gas. during
one particular week, the two cars went a combined total of 1475 miles, for a total gas consumption of 50 gallons. how many gallons were consumed by each of
the two cars that week?

Step-by-step explanation:

x = first car, y = second car

40x + 25y = 1475

x + y = 50...x = 50 - y

40(50 - y) + 25y = 1475

2000 - 40y + 25y = 1475

-40y + 25y = 1475 - 2000

-15y = - 525

y = -525 / -15

y = 35 gallons <=== second car

x + y = 50

x + 35 = 50

x = 50 - 35

x = 15 gallons <== first car

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

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step-by-step explanation:

just for that im not answering