Quadratic equation whose roots are -6 and 6, and whose leading coefficient is 3

If -6 and 6 are the roots, x+6 and x-6 are the factors.

So we have...

f(x)=(x+6)(x-6)

Because the leading coefficient is currently 1, we need to make it 3.

f(x)=3(x+6)(x-6)

f(x)=3x²-108

f(x)=3x²-108

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

560

step-by-step explanation:

giggidy