What is the distance from (23. 5) 0 (23. -12)?

The distance between (23,5) and (23,-12) is 17 units.

Because the x values are equal then this makes this problem much easier. Since y value 5 and y value -12 are in different quadrants then you would add them together (because one value is positive and one is negative). You need to add 5 and the absolute value of -12 which is 12. Adding 5 and 12 and you would get 17.

12+3b -1=-5-b -12-1+5=-b-3b -8=-4b