How many ounces of iodine worth 80 cents an ounce must be mixed with 50 ounces of iodine worth 48 cents an ounce so that the mixture can be sold for 60 cents an ounce?

30 ounces of iodine worth 80 cents an ounce

Step-by-step explanation:

Let

x ----> ounces of iodine worth 80 cents an ounce

we know that

The ounces of iodine (x) worth 80 cents an ounce mixed with 50 ounces of iodine worth 48 cents an ounce must be equal to the mixture (x+50) worth 60 cents an ounce

The linear equation that represent this situation is

solve for x

b. 13

step-by-step explanation:

as there are 13 students in bowling class therefore the most reasonable answer is b as only 13 students are in the bowling class.

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing

step-by-step explanation: