Use technology or a z-score table to answer the question.
the scores for a golf tournament are normally distributed with a mean of 210 and a standard
deviation of 80. ella scored 230 at the tournament
what percent of golfers scored less than ella?
round your answer to the nearest whole number

a: 60%
b: 75%
c: 77%
d: 80%

A:60%

Step-by-step explanation:

Since the scores for a golf tournament are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = scores for the tournament.

µ = mean score

σ = standard deviation

From the information given,

µ = 210

σ = 80

We want to find the probability percent of golfers that scored less than Ella. It is expressed as

P(x < 230)

z = (230 - 210)/80 = 0.25

Looking at the normal distribution table, the probability corresponding to the z score is 0.5987

Therefore, the percent of golfers that scored less than Ella is

0.5987 × 100 = 59.87

Approximately 60%

c is the correct answer

step-by-step explanation:

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