If sin a= 12/13 in quad. 2 , cos b=-4/5 quad 3, how do i find sin (a+b) ?

Therefore

Step-by-step explanation:

Given:

To Find:

Solution:

Using identity,

Now Substitute Sin a we get

As 'a' is in Second Quadrant Cos a is Negative

Similarly,

Now Substitute Cos b we get

As 'b' is in Third Quadrant Sin b is Negative

Now Using Identity

Substituting the values we get

Therefore

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4