Simplify the expression. drag and drop a number into each box to complete the simplification. 160 ÷ parenleftzf (10 − 8)3 2 parenrightzf × 5 = 160 ÷ parenleftzl parenleftzfparenrightzf3 2 parenrightzl × 5 = 160 ÷ parenleftzj 2 parenrightzj × 5 = 160 ÷ × 5 = × 5 =

but which class are u may know that first

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.

x^3-4x^2+3x-2/x^2+1

step-by-step explanation:

factor the numerator and denominator and cancel the common factors