Iam stuck on these 3 questions if at least 2 of them could get answered that would be super : )

  6. (-3/7)√5

  7. 22 ft

  8. 58°

Step-by-step explanation:

6. The relationship between sine and cosine is ...

  sin(θ)² + cos(θ)² = 1

Solving for sine gives ...

  sin(θ) = ±√(1 -cos(θ)²)

In the third quadrant, sine and cosine have the same sign, so ...

  sin(θ) = -√(1 -(-2/7)²) = -√(45/49)

  sin(θ) = (-3/7)√5

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7. You know from SOH CAH TOA that ...

  Sin = Opposite/Hypotenuse

In the relevant triangle, ...

  sin(52°) = (kite height)/(28 ft)

  kite height = (28 ft)·sin(52°) ≈ (28 ft)(0.78801)

  kite height ≈ 22 ft

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8. You know from SOH CAH TOA that ...

  Tan = Opposite/Adjacent

  tan(θ) = (120 ft)/(74 ft) = 60/37

  θ = arctan(60/37) ≈ 58°

The angle of elevation is about 58°.

Comment on these questions

There are a few trig relationships that it is convenient to remember (or keep handy). SOH CAH TOA covers several of them. The relation shown above between sine and cosine is another, as is the corresponding relation between tangent and secant: tan² +1 = sec².

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

the answer is 489

step-by-step explanation: