Endure all, a manufacturer of batteries claims that the lifetime of their batteries is normally distributed with a mean of 500 hr. and a standard deviation of 40 hr. what is the probability that an endure all battery selected at random will last more than 610 hours?

The probability that an Endure All battery selected at random will last more than 610 hours is 0.3%

Z score is used to determine by how many standard deviations the raw score is above or below the mean, The z score is given by:

Given that μ = 500, σ = 40, for x > 610:

From the normal distribution table, P(z > 2.75) = 1 - P(z < 2.75) = 1 - 0.9970 = 0.0030 = 0.3%

Hence the probability that an Endure All battery selected at random will last more than 610 hours is 0.3%

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0.0030

Step-by-step explanation:

We have been given that a manufacturer of batteries claims that the lifetime of their batteries is normally distributed with a mean of 500 hr. and a standard deviation of 40 hr. We are asked to find the probability of selecting a battery that will last more than 610 hours.

Let us find z-score corresponding to 610.

Now, we will use normal distribution table to find probability of getting a area greater than 2.75 as:

Therefore, the probability that an Endure All battery selected at random, will last more than 610 hours, is 0.0030.

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25

44

step-by-step explanation:

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