Box 1 contains 2 red balls and 1 blue ball. box 2 contains 3 blue balls and 1 red ball. a coin is tossed. if it falls heads up, box 1 is selected and a ball is drawn. if it falls tails up, box 2 is selected and a ball is drawn. find the probability of selecting a red ball.

\frac{17}{24}

Step-by-step explanation:

Given that Box 1 contains 2 red balls and 1 blue ball. Box 2 contains 3 blue balls and 1 red ball. A coin is tossed. If it falls heads up, box 1 is selected and a ball is drawn. If it falls tails up, box 2 is selected and a ball is drawn.

P(selecting Box 1) = 0.5 = P(selecting II box) (assuming a fair coin is tossed)

P(Red/Box I ) =

P(Red/Box II) =

Box 1 and Box 2 are mutually exclusive and exhaustive events.

So probability of selecting a red ball.

=  probability of selecting a red ball from box 1 +  probability of selecting a red ball frm box 2

she was supposed to add the hours(38.5) and multiply the amount of money she earned(7.50) resulting in $288.75 .

correct me if i'm wrong and if it is i'm truly sorry.

if you're trying to figure out how much each ounce cost it would be 0.20

cents each ounce