Write an equation of the line that passes through the given point and is parallel to the graph of the given equation.

(0,−5); y=9x

y = 9x – 5

Step-by-step explanation:

The general format of the equation of a line is y = mx + c.

The equation of a line in the slope intercept form is y = 9x.

The slope of the parallel line is same as the slope of the line y = 9x.

So, m = 2.

The equation of a parallel line is y = 9x + a.

Also, this equation pass through the point (0, –5).

⇒ (–5) = 9 (0) + a

⇒ a = –5

Hence, equation of a parallel line is y = 9x – 5.

hope this is what you were asking for!

step-by-step explanation:

jml angle lkj & angle mj = lm