Find the perimeter and area of a rectangle with a length of 2 meters and a width of 3 meters

Let L and W be the length and width of the rectangle, respectively. To solve for the perimeter (P) and area (A), use the following formula:
                                
                                       P = 2 x (L + W)

                                       A = L x W

Substituting the given value for the dimensions, 
 
                                       P = 2 x (2m + 3m) = 10 m
                               
                                        A = 2m x 3m = 6m^2

Therefore, the perimeter is 10m and the area is 6m^2. 

If i'm correct the answer is $15.97

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