Let f(x) be a continuous and differentiable function on theinterval, 0< _ x< _ 1, and let g(x)=f(3x). the table below gives the values of f'(x), the derivatives of f(x). what is thevalue of g'(0.1)?
x 0.1 0.2 0.3 0.4 0.5 0.6
f'(x) 1.01 1.041 1.096 1.179 1.298 1.486

Step-by-step explanation:

We are given that f(x) be a continuous and differentiable function on interval [0,1]

We have to find the value of g'(0.1)

Differentiate w.r.t x

Substitute x=0.1

Substitute the value of f'(0.3) from given table

Hence, the value of g'(0.1)=3.288

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)