Use the compound interest formula, the formula a equals p times 1 plus r over n to the n times t power . if $10,000 is invested at 2 percent daily for 5 years, what is the amount at the end of the term?
a$11,052
b $11,049
c $11,046
d $11,051

Option A is the correct answer.

Step-by-step explanation:

Initial amount deposited into the account is $10000. This means that the principal is

P = 10000

It was compounded daily. This means that it was compounded 365 times in a year. So

n = 365

The rate at which the principal was compounded is 2%. So

r = 2/100 = 0.02

It was compounded for 5 years. So

t = 5

The formula for compound interest is

A = P(1+r/n)^nt

A = total amount in the account at the end of t years. Therefore

A = 10000 (1+0.02/365)^365×5

A = 10000 (1.000055)^1825

A = $11052

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

answer: plz put a pic in so i can answer it

step-by-step explanation: