55: 57
consider points r, s, and t.
which statement is true about the geometric figure that can
contain these points?
no line can be drawn through any pair of the points.
one line can be drawn through all three points.
one plane can be drawn so it contains all three points.
two planes can be drawn so that each one contains all
three points.

step-by-step explanation: i dont

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

yes

step-by-step explanation:

they have to be opposite and reciprocal of eachother.

wertyujhgfdcvb

step-by-step explanation: