Acertain process for removing copper from copper bearing ore had been in use for a period of time, and it is known that this process removes 36 pounds per ton on average. a new process that is supposed to increase the recovered amount is being tested. in a simple random sample of 100 batches of ore, an average of 42 pounds per ton were recovered using the new process. the population of interest in the study is: a. the increase of 6 pounds per ton. b. the miners working with the ore. c. the 100 batches tested. d. ore treated with the new process. e. ore treated with the old process

d. Ore treated with the new process.

Step-by-step explanation:

This is a common practice in statistics, in which we use a sample of a population to infer something about the entire population. We should use a sample of 100.

For example, if we want to know the proportion of residents of Buffalo, New York, who are Bills fans, we are going to take a sample of like, 100 residents, and then use this to estimate for the entire city.

In this problem, we have that:

A new process that is supposed to increase the recovered amount is being tested. In a simple random sample of 100 batches of ore, an average of 42 pounds per ton were recovered using the new process.

So the population of interest is the ore treated with new process. We use a sample of 100 to gather information about the entire population.

So the correct answer is:

d. Ore treated with the new process.

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841