Find an equation of the line that passes through the point (1,-2) and is parallel to the line passing through the point (-2,-1) and (4,3)

2x - 3y = 8 is the equation of the line that passes through the point (1,-2) and is parallel to the line passing through the point (-2,-1) and (4,3)

Solution:

We have to find the equation of the line that passes through the point (1, -2) and is parallel to the line passing through the point (-2, -1) and (4, 3)

Let us first find the slope of line

We know slope of a line and slope of line parallel to it are equal

So we can find the slope of line passing thorugh the point (-2, -1) and (4, 3)

The slope of line is given as:

The points are (-2, -1) and (4, 3)

Substituting the values we get,

Thus the slope of line passing thorugh the point (-2, -1) and (4, 3) is

So the slope of line parallel to it also

Now find the equation of the line that passes through the point (1, -2) with slope

The equation of line in slope intercept form is given as:

y = mx + c ---- eqn 1

Where "m" is the slope of line and c is the y - intercept

Substitute (x, y) = (1, -2) and in eqn 1

Writing in standard form, we get

Thus the equation of line is found

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing

step-by-step explanation:

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step-by-step explanation: