Which of the following is equal to the square root of the cube root of 2? 2 to the power of two thirds 2 to the power of three halves 2 to the power of one third 2 to the power of one sixth

2 to the power of one sixth

Step-by-step explanation:

√ ( ∛(2) )

Transform ∛ to 1/3

√ 2 ^ (1/3)

Transform √ to 1/2

( 2 ^ (1/3) ) ^ 1/2

Connect the powers with ×

( 2 ) ^ ( 1/3 × 1/2 )

Multiply the powers

2 ^ (1/6)

2 to the power of one sixth

(D) 2^1/6

Step-by-step explanation:

i just took the test

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

d i think

step-by-step explanation: